noticethatallwecandoforfactoringistofactoranxoutofeverything.Doingthisgives
x(5×2)=0Fromthefirstfactorwegetthatx=0andfromthesecondwegetthatx=25.Thesearethetwosolutionstothisequation.NotethatifweâdcanceledanxinthefirststepwewouldNOThavegottenx=0asananswer!Letâsworkanothertypeofproblemhere.WesawsomeofthesebackintheSolvingLinearEqua-tionssectionandsincetheycanalsooccurwithquadraticequationsweshouldgoaheadandworkontomakesurethatwecandothemhereaswell.Example2Solveeachofthefollowingequations.(a)1x+1=152×4(b)x+3+3×1=4xx1SolutionOkay
justlikewiththelinearequationsthefirstthingthatweâregoingtoneedtodohereistoclearthedenominatorsoutbymultiplyingbytheLCD.Recallthatwewillalsoneedtonotevalue(s)ofxthatwillgivedivisionbyzerosothatwecanmakesurethatthesearenâtincludedinthesolution.(a)1x+1=152x4TheLCDforthisproblemis(x+1)(2×4)andwewillneedtoavoidx=1and©PaulDawkinsAlgebraâ101â