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write:becarefulwiththesolutionstep. Withthiskindofproblemitisveryeasytomakeamistakehere. x(2y5)=y+42xy5x=y+42xyy=4+5x(2×1)y=4+5xy=4+5x2x1So ifwe’vedoneallofourworkcorrectlytheinversesh

becarefulwiththesolutionstep.Withthiskindofproblemitisveryeasytomakeamistakehere.x(2y5)=y+42xy5x=y+42xyy=4+5x(2×1)y=4+5xy=4+5x2x1So
ifwe’vedoneallofourworkcorrectlytheinverseshouldbe
h1(x)=4+5x2x1Finally
we’llneedtodotheverification.Thisisalsoafairlymessyprocessanditdoesn’treallymatterwhichoneweworkwith.hh1(x)=hh1(x)=h4+5x2x1=4+5x2x1+424+5x2x15Okay
thisisamess.Let’ssimplifythingsupalittlebitbymultiplyingthenumeratorand©PaulDawkinsAlgebra–230–

 

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