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write:u=x5u2=x10Usingthissubstitutiontheequationbecomes 2u2u4=0Thisdoesn’tfactorandsowe’llneedtousethequadraticformulaonit. Fromthequadraticformulathesolutionsare u=1p334Now inorder

u=x5u2=x10Usingthissubstitutiontheequationbecomes
2u2u4=0Thisdoesn’tfactorandsowe’llneedtousethequadraticformulaonit.Fromthequadraticformulathesolutionsare
u=1p334Now
inordertogetbacktox’swearegoingtoneeddecimalsvaluesfortheseso
u=1+p334=1:68614u=1p334=1:18614Now
usingthesubstitutiontogetbacktox’sgivesthefollowing
u=1:68614:x5=1:68614x=(1:68614)15=1:11014u=1:18614:x5=1:18614x=(1:18614)15=1:03473Wehadtouseacalculatortogetthefinalanswerforthese.Thisisoneofthereasonsthatyoudon’ttendtoseetoomanyofthesedoneinanAlgebraclass.Theworkand/oranswerstendtobealittlemessy.©PaulDawkinsAlgebra–132–

 

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